Question

A particle with a charge of −−1.24××10−8C−8C is moving with instantaneous velocity v⃗ v→ = (4.19××104m/s4m/s)i^i^ ++ (−−3.85××104m/s4m/s)j^j^ .

1)What is the force exerted on this particle by a magnetic field B⃗ B→ = (2.70 TT ) i^i^?

Enter the xx, yy, and zz

2)What is the force exerted on this particle by a magnetic field B⃗ B→ = (2.70 TT ) k^k^?

Enter the xx, yy, and zz

Answer #1

A particle with a
charge of −1.24×10−8C is moving with instantaneous velocity
v⃗ = (4.19×104m/s)i^ + (−3.85×104m/s)j^
.
Part A
What is the force
exerted on this particle by a magnetic field
B⃗ = (1.40 T ) i^?
Enter the x,
y, and z components of the force separated by
commas.
Part
B
What is the force
exerted on this particle by a magnetic field
B⃗ = (1.40 T ) k^?
Please solve
and show how you get the z component from...

A particle with a charge of −1.24E-8 C is moving with
instantaneous velocity v⃗ = (4.19E4 m/s)(i) + (−3.85E4
m/s )(j).
What is the force exerted on this particle by a magnetic field
B= (1.50 T ) (i)? Forces in x, y, and z.
What is the force exerted on this particle by a magnetic field
B= (1.50 T ) (k)? Forces in x, y, and z.
Please show ALL work.

A particle with charge −− 5.80 nCnC is moving in a uniform
magnetic field B⃗ =−(B→=−( 1.20 TT )k^k^. The magnetic force on the
particle is measured to be F⃗ =−(F→=−( 3.50×10−7 NN
)i^+()i^+( 7.60×10−7 NN )j^)j^.
A) Calculate the x-component of the velocity of the
particle.
B) Calculate the y-component of the velocity of the
particle.
C) Calculate the scalar product v⃗ ⋅F⃗ v→⋅F→.
D) What is the angle between v⃗ v→v_vec and F⃗ F→?

A particle with a charge of − 5.30 nCnC is moving in a uniform
magnetic field of B⃗ =−(B→=−( 1.25 TT )k^k^. The magnetic force on
the particle is measured to be
F⃗ =−(F→= −( 3.00×10−7 NN )i^+()i^+(
7.60×10−7 NN )j^)j^.
What is the angle between v⃗ v→v_vec and F⃗ F→F_vec?
Express your answer in degrees to three significant
figures.

A particle with charge − 5.10 nC is moving in a uniform magnetic
field B⃗ =−( 1.25 T )k^. The magnetic force on
the particle is measured to be F⃗ =−( 4.00×10−7
N )i^+( 7.60×10−7 N )j^
.
Part A
Are there components of the velocity that are not determined by
the measurement of the force?
yes
no
Part D
Calculate the scalar product v⃗ ⋅F⃗.
v⃗ ⋅F⃗
m/s⋅N
Request Answer
Part E
What is the angle between v⃗
and...

A particle with a charge of − 5.20 nC is moving in a uniform
magnetic field of B⃗ =−( 1.21 T )k^. The magnetic force on the
particle is measured to be F⃗ =−( 3.70×10−7 N )i^+( 7.60×10−7 N
)j^. Calculate the scalar product v⃗ ⋅F⃗ . Work the problem out
symbolically first, then plug in numbers after you've simplified
the symbolic expression.

An object with mass mAmA = 1.6 kgkg , moving with velocity v⃗
A=(4.2iˆ+5.6jˆ−3.0kˆ)m/sv→A=(4.2i^+5.6j^−3.0k^)m/s, collides with
another object of mass mBmB = 4.2 kgkg , which is initially at
rest. Immediately after the collision, the object with mass mAmA =
1.6 kgkg is observed traveling at velocity v⃗
′A=(−2.0iˆ+3.0kˆ)m/sv→′A=(−2.0i^+3.0k^)m/s. Find
the velocity of the object with mass mBmB after the collision.
Assume no outside force acts on the two masses during the
collision.
Enter the xx, yy, and zz components of...

A particle with charge ? 5.50 nC is moving in a uniform magnetic
field B? =?( 1.24 T )k^. The magnetic force on
the particle is measured to be F? =?( 3.40×10?7
N )i^+( 7.60×10?7 N )j^.
(A) Are there components of the velocity that are not determined
by the measurement of the force?
(D)Calculate the scalar product v? ?F? ?
(E) What is the angle between v? and
F? ? Give your answer in degrees?

A particle with charge − 5.70 nC is moving in a uniform magnetic
field B⃗ =−(B→=−( 1.23 T )k^. The magnetic force on the particle is
measured to be F⃗ =−(F→=−( 3.00×10−7 N )i^+(
7.60×10−7 N )j^.
A) Calculate the x-component of the velocity of the
particle.
B) Calculate the y-component of the velocity of the
particle.
C) Calculate the scalar product v⋅F
D) What is the angle between v and F ? Give
your answer in degrees.

An object has a charge of 15.0 mC with a velocity of v⃗
=−2.10×104z^v. At a given instant, the particle enters a region of
space that has both a magnetic field of B⃗ =−2.00×10−6x^B and an
electric field of E⃗ =−12.0x^−4.00y^E. What is the force vector
felt by this charge? You must get all three parts of this question
entirely correct in order to get your points back for the two
questions this corresponds to from the exam.

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