Question

A laboratory electromagnet produces a magnetic field of
magnitude 1.49 T. A proton moves through this field with a speed of
5.88 ✕ 106 m/s.

(a) Find the magnitude of the maximum magnetic force that
could be exerted on the proton.

____N

(b) What is the magnitude of the maximum acceleration of the
proton?

____m/s2

(c) Would the field exert the same magnetic force on an
electron moving through the field with the same speed? (Assume that
the electron is moving in the same direction as the proton.)

Yes

No

Explain.

(d) Would the electron undergo the same acceleration?

Yes

No

Explain.

Answer #1

A laboratory electromagnet produces a magnetic field of
magnitude 1.44 T. A proton moves through this field with a speed of
5.98 ✕ 106 m/s.
(a) Find the magnitude of the maximum magnetic force that could
be exerted on the proton.
N
(b) What is the magnitude of the maximum acceleration of the
proton?
m/s2
(c) Would the field exert the same magnetic force on an electron
moving through the field with the same speed? (Assume that the
electron is...

A proton moves through a magnetic field at 21.1% of the speed of
light. At a location where the field has a magnitude of 0.00603 T
and the proton's velocity makes an angle of 143∘ with the field,
what is the magnitude ?B of the magnetic force acting on the
proton? Use ?=2.998×108 m/s for the speed of light and
?=1.602×10−19 C as the elementary charge.

1. An electron is moving through a magnetic field whose
magnitude is 8.99 × 10-4 T. The electron experiences only a
magnetic force and has an acceleration of magnitude 3.22 × 1014
m/s2. At a certain instant, it has a speed of 8.44 × 106 m/s.
Determine the angle (less than 90o) between the electron's velocity
and the magnetic field.
2.Suppose that an ion source in a mass spectrometer produces
doubly ionized gold ions (Au2+), each with a
mass of...

An electron moves at 2.70×106 m/s through a region in
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field IN M/S^2?)

A proton moves in a direction perpendicular to the magnetic
field lines. The magnetic force exerted on the proton is
perpendicular to both the direction of the velocity and the
direction of the magnetic field.
True
False

A proton is projected perpendicularly into a magnetic field that
has a magnitude of 0.30 T. The field is then adjusted so
that an electron will follow a circular path of the same radius
when it is projected perpendicularly into the field with the same
velocity that the proton had. What is the magnitude of the field
used for the electron?

A proton moves through a region of space where there is a
magnetic field B=(0.41i+0.38j) T and an electric field
E=(2.9i−4.4j)×103V/m. At a given instant, the proton's velocity is
V=(5.1i+2.9j−5.4k)×103m/s.
Determine the components of the total force on the proton.

A proton is moving with a velocity of 4.5 x10³ and forms an
angle that is perpendicular to a uniform magnetic field. The charge
experiences an acceleration of 4.36 x10^-24 m/s2. A second charge
is an electron that is moving at an angle of 40° with respect to
the same. It experiences an acceleration of 2.1 x10^-27 m/s.
a) What is the magnitude of the magnetic field on the
proton?
b) What is the speed of the electron as it...

A proton moves through a region of space where there is a
magnetic field B⃗
=(0.57i+0.37j)T and an electric
field E⃗
=(2.7i−4.0j)×103V/m. At a given
instant, the proton's velocity is
v⃗
=(7.0i+2.8j−4.9k)×103m/s.
Determine the components of the total force on the proton.
Fx, Fy, Fz
=

Constants
In (Figure 1), a beam of protons moves through a uniform
magnetic field with magnitude 2.0 T , directed along the positive
z axis. The protons have a velocity of magnitude
3.0×105 m/s in the x-z plane at an
angle of 30 ∘ to the positive z axis. Find the force on a
proton. The charge of the proton is q=+1.6×10−19C.
SOLUTION
SET UP We use the right-hand rule to find the
direction of the force. The force acts...

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