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A 10 g bullet is fired with 450 m/s into a 10 kg block that sits...

A 10 g bullet is fired with 450 m/s into a 10 kg block that sits at rest on a wooden table 20 cm from the edge of the table. The bullet gets embedded in the block (perfectly inelastic collision). The block, with the embedded bullet, then slides to the edge of the table and drops down with some initial velocity while leaving the edge of the table. The coefficient of kinetic friction between the block and the surface of the table is k = 0.2. If the table is 1 m high, how far from the point directly below the table’s edge does the block land?

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Answer #1

This situation is not possible with 450m/sec speed of bullet. If it is so then the block n embedded bullet can not cross the table. So I solved it with 4500m/sec

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