A hoop (rotational inertia I=MR2 ) of mass M = 1.6 kg and radius R = 50 cm is rolling on a flat surface at a center-of-mass speed of v = 1.2 m/s. Part A The total kinetic energy of the rolling hoop can be expressed as The total kinetic energy of the rolling hoop can be expressed as 34Mv2 12Mv2 Mv2 56Mv2 32Mv2 Request Answer Part B If an external force does 16 J of a positive work on the hoop, what is the new speed of the hoop?.
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