If you know that the Solar intensity at Earth is S0 = 1361 W/m2 , what is the Electric field strength of Solar radiation at Pluto? (you need to know the Sun to Earth distance
aE =1.5x101 1mandtheSuntoPlutodistanceaP =5.9x101 2 m)
We know that:
Intensity = Power/Area = P/(4*pi*R^2)
Since Power of solar radiation will remain constant, So
Intensity is inversely proportional to the square of distance from Source (Sun)
So,
I2/I1 = (R1/R2)^2
I2 = Intenisty of solar radiation at Pluto = I1*(R1/R2)^2
I2 = 1361*[(1.50*10^11)/(5.9*10^12)]^2
I2 = 0.8797 W/m^2 = 0.88 W/m^2
Now relation between Electric field strength and Intensity is given by:
I2 = (1/2)*c*e0*E_max^2
E_max = sqrt (2*I/(c*e0))
c = speed of light = 3*10^8 m/s
e0 = 8.854*10^-12
So,
E_max = sqrt (2*0.88/(3*10^8*8.854*10^-12))
E_max = 25.74 V/m
Let me know if you've any query.
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