At what angular velocity in rpm will the peak voltage of a
generator be 520 V, if its 450–turn, 7.50 cm diameter coil rotates
in a 0.250 T field?
SOLUTION:
N= 450 = number of turns
d= diameter =7.50 m= 7.50*10-2 m
B= 0.250 T= electric field
= Peak voltage
lets the angular velocity
and A= Area
we know that,
peak voltage
The angular velocity is =1046.29 rad/s
ANSWER = 1046.29 rad/s
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