Question

A bullet shot from a small firearm has an initial velocity v0 of 52 m/s at an angle theta = 42 with respect to the horizontal. At the maximum trajectory (max height), we observe that, the bullet explodes into two small pieces both of which are of equal mass. One fragment  immediately after the explosion is therefore zero m/s and it falls vertically.

How long (in seconds) does it take the shell to reach this point trajectory (max height)?

What is the velocity of each fragment at this point (max height) in ?̂, ?̂vector notation?

How far from the firing position does each piece land we assume that there are no external forces, no air resistance, and that the plane is linear.

Answer 1