Question

*A bullet shot from a small firearm has an initial velocity
v0 of 52 m/s at an angle theta = 42 with respect to the horizontal.
At the maximum trajectory (max height), we observe that, the bullet
explodes into two small pieces both of which are of equal mass. One
fragment immediately after the explosion is therefore
zero m/s and it falls vertically.*

*How long (in seconds) does it take the shell to reach this
point trajectory (max height)?*

*What is the velocity of each fragment at this point (max
height) in ?̂, ?̂vector notation?*

*How far from the firing position does each piece land we
assume that there are no external forces, no air resistance, and
that the plane is linear.*

Answer #1

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