Question

On a perfect fall day, you are hovering at low altitude in a hot-air balloon, accelerated neither upward nor downward. The total weight of the balloon, including its load and the hot air in it, is 25000 NN .

Part A

Find the weight of the displaced air.

Express your answer to two significant figures and include the appropriate units.

WW =

nothingnothing

SubmitRequest Answer

Part B

Find the volume of the displaced air.

Express your answer to two significant figures and include the appropriate units.

Answer 1

Part A

Total weight of the balloon including load and air, w = 25000 N

Since, the balloon does not accelerate upward or downward, it is in equilibrium.

From Archimedes’ principle,

Weight of the balloon is equal to the weight of the displaced air

Therefore, the weight of the displaced air = 25000 N

Part B

If m is the mass of displaced air then, mg = 25000

Mass, m = 25000/9.8 = 2551 kg

But, density d = mass/volume

Volume = mass/ density

Density of air = 1.27 kg/m3

Volume = mass/ density = 2551/1.27 = 2008.66 m3

The volume of displaced air, V = 2008.66 m3