A copper pot with a mass of 0.500 kg contains 0.175 kg of water, and both are at a temperature of 23.0 ∘C. A 0.240 kg block of iron at 85.5 ∘C is dropped into the pot. Find the final temperature of the system, assuming no heat loss to the surroundings. Express your answer in degrees Celsius.
Specific heat capacity for copper = 385 J/kg oC
Specific heat capacity of iron = 450 J/kg oC
let the final temperature of the system be T
heat gained by copper and water = heat lost by iron
mcT for copper + mcT for water = mcT for iron
0.5* 385*(T - 23) + 0.175*4186*(T - 23) = 0.24*450*(85.5 - T)
T = 29.53 oC
so the final temperature of the system is 29.53oC
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