Question

A 1.00 kgkg mass oscillates according to the equation x=0.700cos8.60tx=0.700cos⁡8.60t, where xx is in meters and tt is in seconds

Part D

Determine the kinetic energy when x = 0.490 m

Determine the potential energy when x = 0.490 mm .

Answer 1

The Given Equation   describes a Simple Harmonic Motion. Let us compare this equation with the General Equation of SHM given by

, We get

Amplitude A= 0.700 m

And Angular Frequency = 8.60 rad/sec.

Kinetic Energy of a system executing SHM is given by

Given that x = 0.490m

The Potential Energy of the system is given by   

Given that x =0.490 mm ( I am hoping that your have typed out the value correctly)

( Incase the value of x for Potential Energy is 0.490 m then )

Thus the solutions are