Question

function [Ax,Ay,Az]=GravityAcc(M1,X1,Y1,Z1,X2,Y2,Z2)
%We are calculating the acceleration for object 2
G=6.67408*1e-11;

R=?

Am=G*M1/(R^2);
Ax=(X1-X2)/R*Am;
Ay=(Y1-Y2)/R*Am;
Az=(Z1-Z2)/R*Am;
end

What is R in this gravitational acceleration code?

Answer 1

Here ,

Am=G*M1/{R^2}

Am is gravitational acceleration .

According to Newton law of Universal Gravitation states that

F=G*M1*M/{R^2}

Force = Mass*Acceleration

Hence ,

Acceleration = G*M1/{R^2}

Am= G*M1/{R^2}

R is basically the distance between the two objects according to the Newton Law .

Hence , in above relation it is clear that R is distance .

However from other equations it can be seen:

putting value of Am we can find the r to be relative distance function