Question

Two positive point
charges are held fixed on the *x*-axis. Point charge
**A** is located at the origin, and point charge
**B** is located at the position *x = −5.00 cm =
−5.00✕10 ^{-2} m* (on the negative

(A.) The electric
force on charge **A** has magnitude *0.344 mN =
0.344⨯10 ^{-3} N*. What is the electric force (magnitude
and direction) on charge B?

magnitude _______ , in the ___________ direction

(B.) Consider the
location (*x*=0, *y= −12.0✕10 ^{-2} m*), on
the negative

_{x,A}
= (x) magnitude _________N/C, in the ________
direction

_{y,A} = (y) magnitude __________N/C, in the
_________ direction

(C.) Consider the same
location: (*x*=0, *y*= − 12.00 cm), on the negative
*y*-axis.

What are the *x* and *y* components of the electric
field (magnitude and direction) due to just charge
**B** at this location? Let *q _{B} = 6.90
nC = 6.90✕10^{-9} C.*

_{x,B}
= (x) magnitude______N/C, in the _______
direction

_{y,B} = (y) magnitude_________ *N/C*, in
the______direction

(D.) Consider the same
location: (*x*=0, *y*= − 12.00 cm), on the negative
*y*-axis.

What is the electric potential due to both charges
**A** and **B** at this location? (Assume
a reference point of zero potential at infinity:
*V _{∞}=0*.)

*V*
= _______

Answer #1

A point particle with charge q = 4.9 μC is
placed on the x axis at x = −10 cm and a second
particle of charge Q = 7.8 μC is placed on the
x axis at x = +25 cm.
(a) Determine the x and y components of the
electric field due to this arrangement of charges at the point
(x, y) = (10, 10) (the units here are
centimeters).
Ex_____
Ey_____
(b) Determine the magnitude and direction of...

Three point charges are placed on the x-axis. A charge of +2.0
μC is placed at the origin, -2.0 μC to the right at x = 50 cm, and
+4.0 μC at the 100 cm mark.
a. Find the net electric force (magnitude and direction) that
acts on the charge at the origin.
b. Find the net electric field (magnitude and direction) at x =
25 cm.
c. Find the net electric force (magnitude and direction) on a
charge Q...

Two charges are located on the X axis: a +300 pC charge at x =
2.0 cm, and a -400 pC charge at x = -2.0 cm. Find the X Y
components of the electric field at a point on the Y axis with the
coordinates (0, 1.0 cm).

A point charge Q1= +5uC is located on the x axis at x = 5.0
cm, and a second point charge Q2= - 7 uC is located on the x axis
at x = -8.0 cm.
1- Calculate the electric field at the origin due to Q1 and
Q2? (give answer in unit vector notations).
2- Calculate the electric field on the y-axis at point y=+6.0
cm due to Q1 and Q2? (give answer in unit vector notations).
3- What...

A point charge q2 = - 7.00 nC is located at the origin and
charge q1 = 5.00 nC is on the x-axis, 40.0 cm from the origin.
a) Find the magnitude and direction of electric field at point
P, which has coordinates (40.0 cm,-50.0 cm).
b) Find the force on a charge of 5.00 µC placed at point P.

A point charge q2 = - 7.00 nC is located at the origin and
charge q1 = 5.00 nC is on the x-axis, 40.0 cm from the origin.
a) Find the magnitude and direction of electric field at point
P, which has coordinates (40.0 cm,-50.0 cm).
b) Find the force on a charge of 5.00 µC placed at point P.

Three point charges are placed on the x-y plane: a +40.0 nC
charge at the origin, a −40.0 nC charge on the x axis at 15.0 cm,
and a +125.0 nC charge at the point (15.0 cm, 6.00 cm). (a) Find
the total electric force on the +125.0 nC charge due to the other
two. (b) What is the electric field at the location of the +125.0
nC charge due to the presence of the other two charges?

Initially two positive charges lie on the x-axis:
qA is at the origin and qB
is at (23.8 cm,0). The electric field created by these charges is
zero at (6.13 cm,0).
Now the charge on qA is reversed (from
positive to negative). Find the x-coordinate of the point
on the x-axis where the electric field is zero now, in cm. Your
answer must include the sign of the x-coordinate.
HINT: Which charge is larger?

GOAL Use the superposition principle to calculate the electric
field due to two point charges. Consider the following
figure.
The resultant electric field at P equals the
vector sum 1 + 2, where 1 is the
field due to the positive charge q1and
2 is the field due to the negative charge
q2.Two point charges lie along the
x-axis in the x y-coordinate plane.
Positive charge q1 is at the origin, and
negative charge q2 is at (0.300 m, 0). Point...

A point charge q1 = 4.05 nC is located on the x-axis at
x = 2.30 m, and a second point charge q2 = -6.80 nC is on the
y-axis at y = 1.00 m.
A) What is the total electric flux due to these two point
charges through a spherical surface centered at the origin and with
radius r1= 0.800 m?
B) What is the total electric flux due to these
two point charges through a spherical surface centered...

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