Question

1. What is the daughter nuclei produced when LaTeX: _6^{12}C6 12 C undergoes beta - decay.

2. A 65-kg worker is accidentally exposed to a 53-rad dose of gamma radiation. How much energy does the worker absorb?

Answer 1

1) under the process of beta decay , the atomic number of the daughter nuclei is increased by a factor of 1 , whereas the mass number remains unchanged in the daughter nuclei as compared to the parent nuclei.

therefore the daughter nuclei produced of 6C-12 = 7N-12 (which an isotope of nitrogen)

similarly, the beta decay of 6C-14 gives a daughter nuclei of 7N-14 (stable nitrogen atom)

2) absorbed dose = 53 rad

= 53/100 gray = 0.53 gray

RBE (relative biological effectiveness ) of gamma radiation = 1

therefore, energy absorbed for gamma radiation = absorbed dose * mass

= 0.53 * 65

= 34.45 Joules

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