It is becoming more common with large billboards mounted at the top of high masts. In order for the mast not to tip over, the wind load against the sign must be taken into account. The influence of the wind on the sign (wind load) consists for the most part of 'friction drag' and only to a small extent of 'pressure drag' because the air pressure around the sign is approximately atmospheric pressure on all sides.
Is this statement true or false? And please explain why.
The statement is true, as the air pressure around the sign is approximately equal the atmospheric pressure on all the sides, therefore in this case pressure drag have to be taken into the account ( as Pressure drag is caused by the air particles being more compressed (pushed together) on the front-facing surfaces and more spaced out on the back surfaces. This is caused when the layers of air separate away from the surface and begin to swirl or we can say turbulent flow).
Get Answers For Free
Most questions answered within 1 hours.