Question

A 5.0kg object sits on the furthest edge of a large rotating disk with a radius...

A 5.0kg object sits on the furthest edge of a large rotating disk with a radius of 4.0m. The disk rotates at a constant angular speed of 20rev/min. Please use SI units for all answers.

What is the linear speed of the object during this motion?

What is the magnitude of the object

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Answer #1

mass of object = m = 5 kg

radius of disk = r = 4 m

angular speed = W = 20 rev/min = 20 (2/60) = 2.093 rad/s          (since 1 rev = 2 rad , 1 min = 60 sec)

a) linear speed is given as

V = rw

V = (4) (2.093)

V = 8.372 m/s

b)

centripetal acceleration of object is given as ::

a = V2 /r

a = (8.372)2 /4

a = 17.52 m/s2

c)

net force acting on the object = F = ma

F = 5 x 17.52

F = 87.6 N

d) centripetal force acting towards the center of the disk

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