Question

The mass of nitrogen at 20 Celsius and two atmospheres of pressure occupies a volume of 800m^3. What is the variation of volume produced when heated isobaric until 156.6 Celsius? What is the variation of pressure produced from the gas if the gas is heated until the same temperature but with constant volume?

Answer #1

V/T = Constant

Hence

V_{1} /T_{1} =
V_{2 }/T_{2}

Initial volume (V_{1}) = 800 m^{3}

Initial temperature (T_{1}) = 20 ^{o}C =
20+273 = 293 K

Final temperature (T_{2}) = 156.6 +273 = 429.6 K

Now using the above equation

800/293 = V_{2}/429.6

V_{2} = 1172.969 m^{3}

Now if the gas is heated at constant volume then

P/T = Constant

P_{1}/T_{1} = P_{2}/T_{2}

P_{2} = (T_{2}/T_{1})P_{1}

Initial pressure (P_{1}) = 2atm

P_{2} = (429.6/293)*2 = 2.932 atm

Hence this will be the final pressure.

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