Question

N loops of current carrying wire are coiled together to form a
magnetic dipole. The energy required to "twist" the dipole from its
lowest energy state (θ = 0^{o}) to its highest energy state
( θ = 180^{o}) (where θ is the angle between the dipole and
the external B-field) is approximately U = 27 ×10^{−3}
Joules. If the current in the wire is 1.0 Amps, the area of one
loop is 1.0cm x 1.0cm, and the external B-field is 1.0 T through
which the coil rotates, how many loops (N) make up the coil? Answer
to the nearest integer.

Answer #1

If you pass a current through a wire, you can create a magnetic
field. In this class we examine the field from three specific
configurations: an infinitely-long straight wire, a compact loop of
wire (possibly with multiple turns, a coil), or an infinitely long
solenoid (think of an infinitely-long cylinder of loops made by
wrapping a single wire). See the text for an extended description
of all three geometries.
Here’s the challenge: there are three slightly different formulas
used to...

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A net force
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