Question

water flows out of a 2.0 cm radius faucet at a velocity of 36 cm cm/a. How many seconds does it take for 3.0 L of water to exit the faucet?

Answer 1

Write the equation for flow rate.

Q = AV

= Pi*r^2*V

= Pi*2^2*36

= 452.4 cm³/s

Now calculate the time required to exit 3.0 L of water.

Time = Total volume of water/ rate of flow

= (3*1000 cm³)/(452.4 cm³/s) {1 L =1000 cm^3}

= 6.63 s

Thus,the time required to exit 3.0 L of water is  6.63 s.

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