P, Q, and R are three particles with respective electric charges of +1.50 x 10-6 C, -2.00 x 10-6 C, and +2.00 x 10-6 C. They are placed in a straight line with P on the left and R on the right. Each is separated from the adjacent one by a distance of 3.00 m. What is the net force on P?
qP = + 1.5 x 10-6 C
qQ = - 2 x 10-6 C
qR = + 2 x 10-6 C
The separation between P and Q is 3m and the separation between P and R is 6m.
The force between two charges is
The net force acting on P is F = - 2.25 x 10-3 N
The negative sign indicates the force is attractive, hence the charge moves to right if possible.
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