Question

Ten identical capacitors, each with a capacitance of 40 μF, are wired in a simple circuit...

Ten identical capacitors, each with a capacitance of 40 μF, are wired in a simple circuit with a 3 V battery.
(a) If all the capacitors are wired in series, what is the capacitance of the entire circuit? (b) With the capacitors in series, what is the total charge that came out of the positive terminal of the battery in charging all of the capacitors?

(c) If all the capacitors are wired in parallel, what is the capacitance of the entire circuit? (d) With the capacitors in parallel, what is the total charge that came out of the positive terminal of the battery in charging all of the capacitors?

Homework Answers

Answer #1

(a) the capacitors are in series. When capacitors are in series, equivalent capacitance is the reciprocal of the sum of the reciprocal of individual capacitance

1/C = 1/40 + 1/40+ 1/40 + 1/40 + 1/40 + 1/40 + 1/40 + 1/40 + 1/40 + 1/40

C = 40 /10 = 4 uF

(b) Q = CV

Q = 4*3 = 12 uC

(c) when capacitors are in parallel, equivalent capacitance is the sum of individual capacitance

C = 40 + 40 + 40 + 40 +40 + 40 + 40 + 40 + 40+ 40

= 400 uF

(d) Q = CV

= 400*3 = 1200 uC = 1.2 mC

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