Question

A chunk of frozen mercury (the element Hg, not the planet) in an isolated calorimeter has a little warm water splashed on it to warm it up. 1.25 kg of mercury begins the problem at a temperature of -95 C, and is combined with 0.065 kg of water at 15 C. No heat flows to or from the environment. What is the equilibrium state of the system, in terms of temperature, mass of water, mass of ice, mass of solid mercury, and mass of liquid mercury? Note that some or all of the mercury could melt, and some or all of the water could freeze.

The melting point of mercury is -38.8 C, the latent heat of fusion of mercury is 11.4 kJ/kg, the specific heat of liquid or solid mercury is .140 kJ/kg·K (over the range of temperatures in this problem), the melting point of water is 0.00 C, the latent heat of fusion of water/ice is 334 kJ/kg, the specific heat of water is 4.19 kJ/kg·K, and finally, the specific heat of ice is 2.11 kJ/kg·K.

Answer 1

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