Question

# A golfer hits a shot to a green that is elevated 3.30 m above the point...

A golfer hits a shot to a green that is elevated 3.30 m above the point where the ball is struck. The ball leaves the club at a speed of 19.3 m/s at an angle of 35.0˚ above the horizontal. It rises to its maximum height and then falls down to the green. Ignoring air resistance, find the speed of the ball just before it lands.

initial velocity = u = 19.3 m/sec

horizontal component of u = ux = ucos 35 = 15.80 m/sec

Vertical component of u = uy = usin35 = 11.07 m/sec

Vertical distance = y =3.30 m

Acceleration in y direction = ay = -g

If we ignore the air resistance, the horizontal component of velocity will remain constant. hence there is no acceleration along X-direction. Thus, ax = 0

The final velocity along x-direction = vx = ux+axt = ux =15.80 m/sec

The final velocity along y -direction = vy

= 57.8649

vy = 7.60 m/sec

the final speed

The velocity of ball just before land will be 17.53 m/sec

Pls check the calculations

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