given that :
inductance, L = 18 mH = 18 x 10-3 H
inductive reactance, XL = 620 H
now, using a formula :
XL = L { eq. 1 }
where, = 2 f
inserting the value of '' in above eq.
XL = (2 f) L
f = XL / 2 L { eq. 2 }
inserting the values in eq.2,
f = (620 H) / 2 (3.14) (18 x 10-3 H)
f = 620 x 103 / 113.04
f = 5.48 kHz
or f = 5.5 kHz (Answer in two significant figure)
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