Question

A solid cylinder is free to rotate about an axis through its center. If the rotational inertia of the cylinder is .56 kg m^2, and the cylinder is initially at rest, how long must a net torque of 2.1 Nm act on the cylinder to bring it up to an angular speed of 44 rad/s?

Answer 1

Solution:

Using the concept of Angular system

= I

Where

= _f - _i/t where _i = 0 [rest]

Now substitute in above equation,

= I_f/t

t = I_f/

= 0.56 *44/2.1

= 11.73 s.

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