Question

A car is at rest at a stop sign and there is another stop sign 100 m down the road. The car can brake with an acceleration of 16 m/s/s. The car accelerates with a constant rate for some time before accelerating with that braking rate to come to a stop at the second stop sign. The entire trip takes 10 seconds. Let right be positive. Don't round until the end. Report using 3 digits. Don't enter units.

1/ With what acceleration does the car begin its motion? (in m/s/s)

2/ How much time does it accelerate with that acceleration? (in s)

3/ What is the velocity of the car when the braking begins? (in m/s)

Two cars are facing each other. Car A is at rest while car B is moving toward car A with a constant velocity of 20 m/s. When car B is 100 from car A, car A accelerates toward car B with a content acceleration of 5 m/s/s. At the same time, car B begins to brake at a constant rate of 3 m/s/s. Let right be positive. Don't round until the end. Report using 3 digits. Don't enter units.

1/ How much time elapses before the two cars meet? (in s)

2/ How far does car A travel before the two cars meet? (in m)

3/ What is the velocity of car B when the two cars meet? (in m/s)

Answer 1

(1) Daccelerating part ar Vmax t- a Breaker tot + 10 t-sh-106 s-Area under velocity - time graph= 100m = ?X 10 x Vmax = 109 =) Vmax = 20m/ Austo (3) Now slope of Liangle 1 = acceleration t= time needed for aceleration. 2