The figure shows a double-ended slide track. A small block can slide along the track and move up and down either end of the track. The level part of the track has length L= 39 cm, and the coefficient of kinetic friction, LaTeX: \mu_k μ k , is 0.21 in this section. The curved parts of the track are frictionless. The block is released from rest at a height h = 22 cm above the bottom of the track (as shown). Eventually the friction causes the block to stop sliding. Where is the block when it stops?
Express your answer in cm as measured from the left edge of the flat part of the track. Enter only the numerical part in the answer box.
work done by gravitational force Wg = m*g*h
work done by friction Wf = -uk*m*g*x
initial kinetic energy Ki = 0
the block stops after travelling x distance
final kietic energy Kf = 0
total work = change in KE
m*g*h - uk*m*g*x = 0
x = h/uk = 22/0.21 = 10.76 cm
the block comes after travelleing 104.76 cm
length of the track L = 22cm
total distance covered for one complete oscillation d = 44 cm
total distance covered for two complete oscillation d = 88
cm
the distacne from left where th block stops = 104.76 - 88 = 16.76 cm <<<---answer
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