Question

For the circuit shown below, C = 0.114

Answer 1

While discharging the potential is given by

V   =   V₀ * e^-t/RC
?/2   =   ? *e^-t/RC

   0.5   =   e^-t/RC

   e^t/RC     =   2.0

Takinglog            t/RC   =   log_e2.0
3.38 / R * 0.115 *10^-6   =   0.6931

  Resistance   R   =   3.38/ 0.115 * 10^-6 * 0.6931

                           = 4.24*10⁷ ?
  
                          = 42.4 M ?