1. A spectroscopic lamp has been displayed for you to determine the spectroscopic wavelengths in this lab practical. Using the three most prominent spectroscopic lines, fill in the table below from the longest wavelength to the shortest. 3SigFigs no units required.
wavelength (nm) |
2. Using the table provided, identify the gas by the two character abbreviation. _____________
Ne (nm) |
Hg (nm) |
He (nm) |
Cl (nm) |
Kr (nm) |
540 |
440 |
490 |
440.0 |
445 |
610 |
545 |
590 |
490.0 |
560 |
620 |
577/579 |
660 |
650.0 |
590 |
640 |
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650 |
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3. N is the rating of a diffraction grating in lines/centimeter.
Calculate d, the distance between adjacent lines, in micrometers.
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In the figure directly below the quantities A, y, and d are spectrometer parameters which are given in the Spectrometer Parameters below the diagram, The diffraction spots are indicated by the solid dots. Use the equation for constructive interference, d sin(θ)=mλ, enter your answer for the wavelength:
d | 2.4000E+02.4000E+0micrometers |
A | 7.4000E+17.4000E+1mm |
y | 1.0000E+11.0000E+1mm |
4. The calculated wavelength is_______nm to 4SigFigs.
1) There is supposed to be a spectrum along with this question.
As I have seen this question earlier, I can answer this part.
The most prominent wavelengths in the spectrum are at
2) To get the name of the gas used in the lamp, we have to compare the prominent wavelengths from the lamp in part 1 and the table given.
From the table, we can see that the wavelengths are closest to mercury.
3) The number of lines per centimetre of the grating is
N = 8*10^2
So, distance between two lines is
d = 1/(8*10^2) = 0.00125 cm = 12.5*10^-6 m = 12.5
4) It is given that
For a grating spectrometer,
Taking m = 1
Using the values from the question
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