Question

1. You shoot an arrow from a compound bow straight up into the air, and it goes 7.6 m above the height you shot it from before it falls back down. If you now shoot the arrow at a 22° angle above the horizontal, what will its new maximum height be?

Answer 1

Solution:

From the information given,

Step-1:

Find the initial velocity from case-1 of vertical,

Using kinematics,

v² - u² = 2aH_max,

Given v = 0, a = -9.81m/s². and H_max = 7.6 m

0² - u² = 2*-9.81*7.6

u = 12.2 m/s.

Step-2:

For the projectile with initial velocity at an angle = 22^o.

H_max = u²Sin²/2g

= 12.2²Sin²22^o/2*9.81

= 1.07 m.

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