Question

A wheel of diameter 0.35 m is rotating at 2700 rpm.

Calculate its angular velocity in radians per second. Use 'rad/s' for your units.

What is the linear speed of a point on the edge of this wheel?

What is the linear acceleration of a point on the edge of this wheel?

Answer #1

**Solution:-**

**Given –**

Diameter (D) = 0.35 m; radius(r) = 0.35m/2 = 0.175

**a)** **Calculate
angular velocity**

ω = 2700 rpm * (2*π / 60)

**ω = 282 rad/s**

**b)** **Calculate
linear speed**

Using formula,

V = r*ω

Substitute given values in above formulas

V = 0.175 * 282 rad/s

**V = 49.45 m/s**

**c)** **Calculate
linear acceleration**

a = r*ω^2; a = v^2 / r

Substitute given values in above formula

a = (49.45) ^2 / 0.175

**a = 13973 m/s^2**

**Result:-**

**a)** **angular
velocity =** **282 rad/s**

**b)** **linear
speed = 49.45 m/s**

**c)** **linear
acceleration = 13973 m/s^2**

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