Question

A simple pendulum makes 116 complete oscillations in 2.90 min at
a location where *g* = 9.80 m/s^{2}.

(a) Find the period of the pendulum.

s

(b) Find the length of the pendulum.

m

Answer #1

a)Number of oscillations = 116

Time=2.9 minutes = 2.9*60 s = 174 seconds.

So, period=(number of oscillation)/time = 116/174=0.6667 seconds.

b)For simple pendulums, T=2*(l/g)^0.5, where T is period, l is length of the pendulum and g is gravitational acceleration.

Here,T=0.6667 seconds

So, 0.6667 = 2*(l/9.8)^0.5

=>l=9.8*[0.6667/(2)]^2 = 0.11 m.

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