Question

As we have discussed in class, when a system is at equilibrium, its entropy, S, is...

  1. As we have discussed in class, when a system is at equilibrium, its entropy, S, is maximized, and its Gibb’s free energy, G, is minimized. Do these facts make sense when the natural direction of change for an isolated system is taken into account?
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In actual processes we know that entropy increases as processes go forward or remains constant. It cannot decrease in actual processes. Now case of an isolated system , the natural direction of process will be carried on the expanse of the free energy of the system because free energy is the maximum amount of work system can do at constant temperature. As system is an isolatation  the work done will decrease the free energy as natural direction of process will take it to lowest free energy state or to equilibrium where entropy would be maximum. So going in forward direction will increse the entropy while decrease the free energy on natural direction or spontaneous process. Usually in spontaneous process in isolated system , it is characterised by increase in the entropy.

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