A heat engine operates between a reservoir at 28°C and one at 311°C. What is the maximum efficiency possible for this engine?
Solution :
Maximum efficiency of a heat engine operating between 2 temperature is given by
= = Temperature of reservoir at lower temperature in kelvin = 273+28 = 301 K
= = Temperature of reservoir at higher temperature in kelvin = 273+311 = 584 K
hence
.............Answer
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