Question

⦁   A blade of length 6m has an angular speed of 6.5 revolution per second and has an angular acceleration of 1.3 revolution per second squared. What is the tangential speed and tangential acceleration midway of the blade?

Answer 1

Answer:

Given, length of the blade is L = 6 m, angular speed = 6.5 revolution/s

Converting into rad/s,

= 2 (6.5 rev/s) = 40.82 rad/s.

Therefore, tangential speed at the midway of the blade is v = r , where r = L/2

Then, v = (40.82 rad/s) (6m/2) = 122.46 m/s.

and angular acceleration = 1.3 revolutions/s2

Then, = 1.3 revolution/s2 = (1.3) 2 rad/s2 = 8.16 rad/s2

Then, tangential acceleration at the midway of the blade is a = .r = (8.16 rad/s2) (6 m/2) = 24.48 m/s2