Question

A small object begins a free-fall from a height of ?=81.0 m at ?0=0 s . After τ=2.60 s , a second small object is launched vertically up from the ground with an initial velocity of ?0=39.9 m/s . At what height from the ground will the two objects first meet?

Please clearly mark the solution. Please take a clear picture (if taking a photo). Please write legibly (if handwriting). Please make sure the answer is CORRECT.

Answer 1

So first object free fall begins at t=0 s

so,

so,

and second object strarts its motion upward at t= 2.6 s so , we write

so, when they first meet at they are at same height from ground so,eqiuating both

Now H =81 m

g =9.8 m/s^2

v0= 39.9 m/s

so solving for v we get

t= 3.332 sec

So height from the ground we calculate using this equation

y = 26.6 m

so at this height from ground two objects first meets.