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Find the period of the pendulum 1.17 m long in elevator moving with 1.1 m/s2 dawn?...

Find the period of the pendulum 1.17 m long in elevator moving with 1.1 m/s2 dawn? Calculate to one decimal.

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Answer #1

The elevator is moving at 1.1 m / s2 downward.

The acceleration due to gravity g = 9.8 m / s2 is also acting on the pendulum downward.

Therefore, net acceleration felt by the pendulum is a = g - 1.1 m / s2 = ( 9.8 - 1.1 ) m / s2 = 8.7 m / s2.

Length of the pendulum = L = 1.17 m.

Hence, time period of the pendulum = T = 2 ( L / a ) = 2 x 3.14 x ( 1.17 / 8.7 ) s ~ 2.3 s.

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