Question

Analysis of Procedure 3 1. If the graph of distance vs. time from Procedure 3 is...

Analysis of Procedure 3

1. If the graph of distance vs. time from Procedure 3 is nonlinear, square the time; and plot the graph of distance vs. time squared.

2. Describe the relationship between time and distance in the language of direct proportions.

3. From the relationship between distance and time can you find the time for a distance of 75 cm? Explain your reasoning.

4. If you said that you cannot find the time for a distance of 75 cm, can you use another relationship to find the time for that distance? If so, which one?

5. Use the relationship and find the time for a distance of 75 cm. Is this interpolation or extrapolation?

6. From the relationship between distance and time can you find the time for a distance of 200 cm? Explain your reasoning.

7. If you said that you cannot find the time for a distance of 200 cm, can you use another relationship to find the time for that distance? If so, which one?

8. Use the relationship and find the time for a distance of 200 cm. Is this interpolation or extrapolation?

Data:

Distance (cm) 20 40 60 80 100 120 140 160
Time (sec2) 3:61 6:55 9:73 12:89 16:24 19:98 23:81 27:56
Science   Advanced-Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

1.

2. Distance now if initial velocity u=0 then that is distance is proportional to square of time

3. take cursor at y axis=75. that is t^2.take root of this for t.

4. take slop on the distance vs t^2 graph. slope is f. then distance 75. then 75/slope is t^2. the take root of t^2. that time for s=75 cm.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Questions 1 through 6 work with the length of the sidereal year vs. distance from the...
Questions 1 through 6 work with the length of the sidereal year vs. distance from the sun. The table of data is shown below. Planet Distance from Sun (in millions of miles) Years (as a fraction of Earth years) ln(Dist) ln(Year) Mercury 36.19 0.2410 3.5889 -1.4229 Venus 67.63 0.6156 4.2140 -0.4851 Earth 93.50 1.0007 4.5380 0.0007 Mars 142.46 1.8821 4.9591 0.6324 Jupiter 486.46 11.8704 6.1871 2.4741 Saturn 893.38 29.4580 6.7950 3.3830 Uranus 1,794.37 84.0100 7.4924 4.4309 Neptune 2,815.19 164.7800 7.9428...
1) how is change in velocity shown on a position vs time graph? 2) how is...
1) how is change in velocity shown on a position vs time graph? 2) how is change in velocity shown on a velocity vs time graph? 3) how is change in velocity shown an acceleration vs time graph? 4) how can position be found from a velocity vs. time graph? 5) how can velocity be found from an acceleration vs. time graph? 6) how is acceleration shown on a position vs. time graph? 7) how is velocity shown on a...
Distance from Bar Magnet (cm) 10 cm 9 cm 8 cm 7 cm 6 cm 5...
Distance from Bar Magnet (cm) 10 cm 9 cm 8 cm 7 cm 6 cm 5 cm 4 cm 3 cm 2 cm 1 cm Magnetic Field Strength (gauss) 0 0 1 3 4 8 13 22 44. 82 what can be said about the mathematical relationship between the field strength B and distance d based on this fit?
Graph 1: [A565]t vs time (sec) y=mx+b y=-0.0277x +0.5852 (graph is curved)    2 0.644 3...
Graph 1: [A565]t vs time (sec) y=mx+b y=-0.0277x +0.5852 (graph is curved)    2 0.644 3 0.61 4 0.479 5 0.434 6 0.39 7 0.353 8 0.319 9 0.291 10 0.261 11 0.238 12 0.207 13 0.182 14 0.161 15 0.146 16 0.132 17 0.117 18 0.111 19 0.095 20 0.086 21 0.071 Graph 2: ln [A565]t vs time (sec) y=mx+b y=-0.112x-0.2368 (graph is almost linnear, sloped downward) 2 -0.44 3 -0.494 4 -0.736 5 -0.835 6 -0.942 7 -1.041...
PART 1: THE ELECTRIC FIELD Procedure: Assemble in groups of 2-3 around the pod computers. You...
PART 1: THE ELECTRIC FIELD Procedure: Assemble in groups of 2-3 around the pod computers. You may also use a laptop or tablet. Open the Charges and Field simulation: http://phet.colorado.edu/en/simulation/charges-and-fields and click on the “play” symbol to open. Once the simulation opens, check the box next to grid. Your instructor will show you a few things about this simulation before you begin. Explore: Answer all questions and all parts below. 1. First, explore by placing a 1 nC positive charge...
An object is placed 4 cm away from a concave lens of focal length 3 cm....
An object is placed 4 cm away from a concave lens of focal length 3 cm. A convex lens of focal length 5 cm is placed 4 cm away from the concave lens in the same direction (so the distance between convex lens and the object is 8 cm). Use any method to figure out if the final image is real/virtual, upright/inverted and find its distance from the convex lens. Explain in thorough detail. draw a proper ray diagram for...
1. A mass is attached to a horizontal spring, and oscillates with a period of 1.2...
1. A mass is attached to a horizontal spring, and oscillates with a period of 1.2 s and with an amplitude of 14 cm. At t = 0 s, the mass is 14 cm to the right of the equilibrium position. a) Write down the function for the position, velocity, and acceleration of the mass as a function of time. The only variable you should have in your expressions is time. Make sure you indicate the units for each function....
1-a body with m = 3 Kg and it's velocity at certain time is 9 m/s...
1-a body with m = 3 Kg and it's velocity at certain time is 9 m/s and he cross a distance 18 m at 3 second , tell what is the force acting on it and find the magnitude of the force . 2- a thin plate with area 0.08 m2 , isolated from another plate by liquid layer with thickness 3 mm. if a tangent force acting on it by 6.3 N the it moved by velocity 33 cm/s,...
Let f(x) = x*(2-x) if x>=0, or x*(x+2) if x<0 i) graph the function from x=-3...
Let f(x) = x*(2-x) if x>=0, or x*(x+2) if x<0 i) graph the function from x=-3 to x=+3. If you like WolframAlpha, use Piecewise[{{x*(2-x),x=>0},{x*(x+2),x<0}}] If you like Desmos, use f(x)= {x>=0:x*(2-x), x<0:x*(x+2)} (for some reason, when you paste that it, it forgets the first curly-brace { so you’ll need to add it in by hand) Or, you can use this, but it makes it less clear how to take the derivative: f(x) = -sign(x)*x*(x - 2*sign(x) ) ii) Find and...
true/false An unweighted path length measures the number of edges in a graph. Breadth first search...
true/false An unweighted path length measures the number of edges in a graph. Breadth first search traverses the graph in "layers", beginning with the closest nodes to the ending location first. The computer knows about neighbors by checking the graph storage (such as the adjacency matrix or the adjacency list). Breadth first traversals use a stack to process nodes. The weighted path length is the sum of the edge costs on a path. Dijkstra's shortest path algorithm can be used...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT