A boy tosses a football upward. If the football rises a vertical distance of 7.2 m and the boy catches it at the same point he released it, what is the velocity of the ball just before he catches it?
Gravitational acceleration = g = -9.81 m/s2 (Negative as it is directed downwards)
Vertical distance the football rises to = H = 7.2 m
Velocity of the football at maximum height = V1 = 0 m/s
Velocity of the football just before the boy catches it = V2
Time taken by the football to reach the boy's hands from the maximum height = T
When the boy catches the football the displacement of the football is downwards therefore the vertical displacement of the ball is negative.
T = 1.212 sec
V2 = V1 + gT
V2 = 0 + (-9.81)(1.212)
V2 = -11.9 m/s
Velocity of the football just before he boy catches it = -11.9 m/s
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