Question

A pendulum with a period of 2.00000 s in one location

(* g* = 9.80 m/s

is moved to a new location where the period is now 1.99757 s.
What is the change in acceleration (in m/s^{2}) due to
gravity at its new location?

Answer #1

**Time period of a pendulum is**

**Assuming L to be the same in both
locations,**

**first location:**

**second location:**

**Let
be the acceleration due to gravity in second location**

**Therefore,**

**dividing these equations, we get**

**Change in acceleration is**

When a pendulum with a period of 2.00000 s in one
location
(g = 9.80 m/s2)
is moved to a new location from one where the
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