Question

In the Bohr model, the electron moves in a circular orbit around the nucleus with a radius of 5 . 29 × 10 - 11 m . What is the magnitude of the electric force between the electron and the proton?

Answer 1

here we are given that,

radius =  5 . 29 × 10^- 11 m

charge of electorn = -1.602 x 10^-19 coulombs.

charge of proton = 1.602 x 10^-19 coulombs.

now the electric force between the electron and the proton given as

F = Kq1q2/r2 ....................1

as here we can see that electorn is moving in circular orbit of radius r and proton is present at the centre so that we can take the distance between electron and proton is the radius

on pluging the values on equation 1 we get,

F = Kq1q2/r2 = 9*109*-1.602 x 10^-19 *1.602 x 10^-19 /  5 . 29 × 10^- 11 = - 8.2332467 * 10-8 N

hence the  magnitude of the electric force between the electron and the proton would be ,

F = 8.2332467 * 10-8 N