A horizontal 804-N merry-go-round is a solid disk of radius 1.44 m and is started from rest by a constant horizontal force of 49.8 N applied tangentially to the edge of the disk. Find the kinetic energy of the disk after 2.91 s.
Answer :
Rotational Kinetic energy is equal to: 1/2 x moment of inertia (I), multiplied by the angular velocity (w) squared.
In order to find the angular velocity (w), we first need to find the angular acceleration (a).
We know that the force is acting tangentially to the disk, creating a torque on the disk. In this case, the torque is equal to the force times the radius (r) of the disk. T
torque is also equal to the moment of inertia times the radial acceleration (a).
Set the two Torque values equal and solve for the radial acceleration (a):
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