Question

A horizontal 804-N merry-go-round is a solid disk of radius 1.44 m and is started from...

A horizontal 804-N merry-go-round is a solid disk of radius 1.44 m and is started from rest by a constant horizontal force of 49.8 N applied tangentially to the edge of the disk. Find the kinetic energy of the disk after 2.91 s.

Homework Answers

Answer #1

Answer :

Rotational Kinetic energy is equal to: 1/2 x moment of inertia (I), multiplied by the angular velocity (w) squared.

In order to find the angular velocity (w), we first need to find the angular acceleration (a).

We know that the force is acting tangentially to the disk, creating a torque on the disk. In this case, the torque is equal to the force times the radius (r) of the disk. T

torque is also equal to the moment of inertia times the radial acceleration (a).

Set the two Torque values equal and solve for the radial acceleration (a):

  

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A horizontal 803-N merry-go-round is a solid disk of radius 1.59 m and is started from...
A horizontal 803-N merry-go-round is a solid disk of radius 1.59 m and is started from rest by a constant horizontal force of 50.2 N applied tangentially to the edge of the disk. Find the kinetic energy of the disk after 2.97 s.
A horizontal 810-N merry-go-round of radius 1.70 m is started from rest by a constant horizontal...
A horizontal 810-N merry-go-round of radius 1.70 m is started from rest by a constant horizontal force of 55 N applied tangentially to the merry-go-round. Find the kinetic energy of the merry-go-round after 2.0 s. (Assume it is a solid cylinder. Also assume the force is applied at the outside edge.)
3.            A horizontal 800.N merry-go-round of radius 1.50 m is started from rest by a constant...
3.            A horizontal 800.N merry-go-round of radius 1.50 m is started from rest by a constant horizontal force of 50.0 N applied tangentially to the merry-go-round. (a) Find the kinetic energy of the merry-go-round after 3.00 s. (Assume it is a solid cylinder.) (b) A 10.0kg mass is dropped vertically onto the merry-go-round at a point 1.40 m from the center of rotation and sticks to the merry-go-round. Determine the final angular speed of the system.
A merry-go-round on a playground consists of a horizontal solid disk with a weight of 795...
A merry-go-round on a playground consists of a horizontal solid disk with a weight of 795 N and a radius of 1.58 m. A child applies a force 49.5 N tangentially to the edge of the disk to start it from rest. What is the kinetic energy of the merry-go-round disk (in J) after 2.90 s?
A 170-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m...
A 170-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope about the rim of the disk and pulling on the rope. What constant force would have to be exerted on the rope to bring the merry-go-round from rest to an angular speed of 0.600 rev/s in 2.00 s? (State the magnitude of the force.)
A merry-go-round (radius = 4 m) with a perfect frictionless bearing is pushed with a force...
A merry-go-round (radius = 4 m) with a perfect frictionless bearing is pushed with a force of 24 N by a young girl. She pushes with a constant force that is oriented tangentially to the edge of the merry-go-round. After she pushes the merry-go-round through 14 full rotations (at which point she lets go) it is spinning with an angular speed of 3 rad/s. a) What is the moment of inertia of the merry-go-round? b) After the girl lets go,...
A child of mass m=15kg stands on a merry-go-round. The radius of the merry-go-round is R=2m...
A child of mass m=15kg stands on a merry-go-round. The radius of the merry-go-round is R=2m and the mass is M=75kg. The merry-go-round is considered to be a solid disk. The merry-go round initially at rest and the child stands near the edge. What will the angular velocity of the merry-go-round be if the child jumps off a.) In the radial direction with a velocity of +4m/s? b.) perpindicular to the radial direction with a velocity of +4m/s? c.) At...
a 50.0 kg child is on a 200. kg merry-go-round with a radius of 1.50 m....
a 50.0 kg child is on a 200. kg merry-go-round with a radius of 1.50 m. the child starts at 0.5 m from the center and moves to the edge. the child's parent accelerates the merry-go-round from rest at 0.75 rad/s^2 to a speed of 1.5 rad/s. How long did the parent push the merry-go-round? how much force is required to hold the child when at 0.5 m from the center? determine the kinetic energy of the system when moving...
A child exerts a tangential 58.5 N force on the rim of a disk-shaped merry-go-round with...
A child exerts a tangential 58.5 N force on the rim of a disk-shaped merry-go-round with a radius of 2.99 m. If the merry-go-round starts at rest and acquires an angular speed of 0.1250 rev/s in 5.00 s, what is its mass?
A playground merry-go-round is a large disk of mass 10.0 kg and radius 2.00 m. The...
A playground merry-go-round is a large disk of mass 10.0 kg and radius 2.00 m. The merry-go-round is initially at rest. A physics teacher pushes on the rim for 24.0 s to accelerate it with constant angular acceleration until the merry-go-round has completed a total of 9.00 full revolutions. a. What is the final angular velocity after 24.0 s? b. How much total work did the teacher do on the merry-go-round? (You may assume the axle for the merry-go-round is...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT