Question

When walking toward a concave mirror you notice that the image flips at a distance of 0.55 mm. What is the radius of curvature of the mirror?

Answer 1

We know, a concave mirror forms a real inverted image for object distance greater than the focal length.

And it forms a virtual and erect image for object distance less than the focal length.

The focal length is equal to half of the radius of curvature or radius of curvature is double the focal length.

Now, in our problem it is given that the image flips at distance 0.55 mm, it means the focal length is 0.55 mm.

Therefore, the radius of curvature of the mirror is R = 2* focal length = 2*0.55 mm = 1.1 mm [answer]