The acceleration of a particle moving only on a horizontal xy plane is given by ModifyingAbove a With right-arrow equals 4t ModifyingAbove i With caret plus 5t ModifyingAbove j With caret, where ModifyingAbove a With right-arrow is in meters per second-squared and t is in seconds. At t = 0, the position vector ModifyingAbove r With right-arrow equals left-parenthesis 24.0mright-parenthesis ModifyingAbove i With caret plus left-parenthesis 49.0mright-parenthesis ModifyingAbove j With caret locates the particle, which then has the velocity vector ModifyingAbove v With right-arrow equals left-parenthesis 4.00 m/s right-parenthesis ModifyingAbove i With caret plus left-parenthesis 3.40 m/s right-parenthesis ModifyingAbove j With caret. At t = 6.00 s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis?
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