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When the current in a long, straight, air-filled solenoid is changing at the rate of 3000...

When the current in a long, straight, air-filled solenoid is changing at the rate of 3000 A/s, the voltage across the solenoid is 0.600 V. The solenoid has 1200 turns and uniform cross-sectional area 25.0 mm2. Assume that the magnetic field is uniform inside the solenoid and zero outside, so the inductance formula L=μ0AN2/l for a solenoid with N turns, uniform cross-sectional area A, and length l, applies.

What is the magnitude B of the magnetic field in the interior of the solenoid when the current in the solenoid is 3.00 A?

Express your answer with the approppriate units.

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