Question

Exactly 1.27 moles of an ideal gas undergoes an isothermal expansion (T = 259 K) from state A to state B and then returns to state A by another process. The volume of the gas in state B is three times its initial volume.

(a) For the process AB, find the work done by the gas and its change in entropy. work = J change in entropy = J/K

(b) Find the gas's change in entropy for the process BA. J/K

Answer #1

Suppose 4.00 mol of an ideal gas undergoes a reversible
isothermal expansion from volume V1 to volume V2 = 8V1 at
temperature T = 300 K. Find (a) the work done by the gas and (b)
the entropy change of the gas. (c) If the expansion is reversible
and adiabatic instead of isothermal, what is the entropy change of
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10-3
m3) R = 8.314 J/(mole
K)
a) What is the entropy change
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b) What is the entropy change
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A sample consisting of 2.5 moles of ideal gas (Cp,m
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different paths: a) reversibly and b) irreversibly. For these two
paths, compare the relative magnitude (i.e. greater/same/lower) of
the expansion work that ideal gas does to the surroundings. Make
sure to justify your answer (suggestion to use a P-V diagram).

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the volume and pressure are allowed to change. In such a proces the
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b.) If the...

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1 mole of a gas undergoes a mechanically reversible isothermal
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V=RTP+b where V is the molar specific volume, and Tand Pare
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(include sign) b) Change...

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