Consider a conducting rod of length 2.50 m immersed in a uniform magnetic field with strength 4.00 T and oriented as shown in the figure. Assume that this rod is part of a closed conducting loop and is free to move. If this rod moves with speed 4.00 m/s in the +? − direction, what is the magnitude of the induced emf?
the magnitude of the induced emf is E = Blv
= 4 * 2.5 * 4
= 40 V
Get Answers For Free
Most questions answered within 1 hours.