Question

Astronauts on our moon must function with an acceleration due to gravity of 0.170g .If an astronaut can throw a certain wrench 11.0 m vertically upward on earth, how high could he throw it on our moon if he gives it the same starting speed in both places? How much longer would it be in motion (going up and coming down) on the moon than on earth? IN SECONDS

Answer 1

Here ,

for the starting speed at the earth

height = u^2/(2 * g)

11 = u^2/(2 * 9.8)

u = 14.7 m/s

Now, for the height at moon

height at moon = u^2/(2 * a)

height at moon = 14.7^2/(2 * 0.170 * 9.8)

height at moon = 64.7 m

the height reached at moon is 64.7 m

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for the time taken

extra time taken = time of flight on moon - time of flight on earth

extra time taken = 2 * 14.7/(0.170 * 9.8) - 2 * 14.7/(9.8)

extra time taken = 14.65 s

the extra time taken on the moon is 14.65 s