A 27 kg box is being dragged across a smooth floor by a rope for a distance of 7 m. The rope is pulling with a tension of 35 N, directed 22 above the horizontal. What is the change in kinetic energy of the box?
There are three forces acting on the box- i) pulling force by the force, F=35 N, which is directed 22° above the horizon ii) weight of the box, directed vertically downward iii) Normal reaction force, N directed vertically upward.
The displacement d=7 m of the box is along the horizontal direction.
Work done by a force, W = force * displacement* cos(). Where is the angle between displacement and the force.
Weight of the box and the normal force are perpendicular to the displacement, so they don't do any work.
Work done by the applied pulling force, W = F*d*cos(22°) = 35 N * 7 m * cos(22°) = 227.2 joule.
By kinetic energy-work theorem,
Change in kinetic energy of the box = work done by the force = 227.2 joule.
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