Question

The density of silver is 10.49 g/cm³ how much does a block with dimensions 4in x 2in x 8in weigh?

Answer 1

Given

Density of silver ( d )= 10.49 g / cm​​​​​3

d = 10.49*103 kg/m​​​​​​3​​​

And dimensions of silver block = 4in*2in*8in

Since 1inch = 0.0254 meter

So dimensions = 0.1016m*0.0508m*0.2032m

Now volume ( v ) = 1.049*10-3 m​​​​​​3

Since we know that-

Density (d) = mass (m) / volume (v)

Putting the values-

10.49*103 = m / 1.049*10-3

m = 10.49*103 * 1.049*10-3 kg

m = 11 kg

So mass of the silver block is 11kg.

Now weigh on earth = mg

Where g = gravitational acceleration

So weigh of silver (w) = 11*9.8 N

w = 107.8 N

So weight of the silver block is 107.8 Newtons.