Question

A particle travels along a straight line with a velocity v=(12−3t^2) m/s , where t is in seconds. When t = 1 s, the particle is located 10 m to the left of the origin.

Determine the displacement from t = 0 to t = 7 s.

Determine the distance the particle travels during the time period given in previous part.

Answer #1

A particle that moves along a straight line has velocity v ( t )
= t^2e^− 2t meters per second after t seconds. How many meters will
it travel during the first t seconds (from time=0 to time=t)?

A particle is moving along a straight line and has acceleration
given by a(t) = 20t^3+12t^2}. Its initial velocity is v( 0 ) = 4 m
/ s and its initial displacement is s( 0 ) = 5 m. Find the position
of the particle at t = 1 seconds.

[6:10 p.m., 2020-04-17] Bhavya Pipalia: The velocity of a
particle constrained to travel along a straight path is given by
v(t) = 48 – 16t m/s, where t
is in seconds. The particle is located at a position of 28 m at t =
0 s.
a) Determine the position, velocity and acceleration of the
particle at t = 2 s.
b) What is the total distance travelled by the particle in the
first 5 s of motion?
c) What...

The velocity function, in feet per second, is given for a
particle moving along a straight line. v(t) = t^3 − 10t^2 + 29t −
20, 1 ≤ t ≤ 6 (a) Find the displacement. (b) Find the total
distance that the particle travels over the given interval (solve
in fraction form).
a.) displacement ANSWER IS 175/12 Correct: Your answer is
correct.
b.) Find total displacement. (I only need to solve part B).
=?

A particle is moving along a straight line and has acceleration
given by a(t) = 20t^3+12t^2}. Its initial velocity is: v(0) = 4 m/
and its initial displacement is s(0) = 5 ms. Find the position of
the particle at t = 1 seconds.
10 m
5 m
11 m
4 m
2m

A particle is moving along a coordinate line with an
acceleration of a(t) = 3t m/sec2. If s(0) = 2 m and v(0) = 18
m/sec, find the position of the particle after 1 sec.

A particles velocity along the x-axis is described by v(t) = At
+ Bt^2, where t is in seconds, velocity is in m/s^2, A = 1.18m/s^2
and B = -0.61m/s^3. What is the distance traveled, in m, by the
particle between times t0=1.0 and t1=3.0? please show steps and
calculations

If a ball is kicked straight north along a line with a velocity
of 7 m/s and a 4 m/s wind is blowing northwest at an angle of 43
degrees (west of north), what is it's east/west displacement from
the line after 7 seconds?

A particle moves in a straight line with the given velocity
?(?)=9cos(?) (in m/s). Find the displacement and distance traveled
over the time interval [0,9?]. Calculate the displacement and
distance.

The velocity function (in meters per second) is given for a
particle moving along a line.
v(t) =
t2 − 2t −
8, 1 ≤ t ≤ 5
(a) Find the displacement. (m)
(b) Find the distance traveled by the particle during the given
time interval. (m)

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